Assuming that type int takes 4 bytes in memory, what do you think the address of b will be?

Assuming that type int takes 4 bytes in memory, what do you think the address of b will be?

You have the following C++ function.
void foo() {
 int a = 10;
 if (true) { int b = 20; }
 int c = 30;
 cout << &a << “ “ << &c << endl;
}


When you call it, it prints the following output:

0x00000000abcabcab 0x00000000abcabcb3

Assuming that type int takes 4 bytes in memory, what do you think the address of b will be? :



  1.     0x00000000abcabcaf
  2.     0x00000000abcabca7
  3.     0x00000000abcabcb7
  4.     There is no address for b because it is allocated on the heap.